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x^2-9.6x+19.2=0
a = 1; b = -9.6; c = +19.2;
Δ = b2-4ac
Δ = -9.62-4·1·19.2
Δ = 15.36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9.6)-\sqrt{15.36}}{2*1}=\frac{9.6-\sqrt{15.36}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9.6)+\sqrt{15.36}}{2*1}=\frac{9.6+\sqrt{15.36}}{2} $
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